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独立事件的组合概率的笔记

The sum of the probabilities of all of the possible events should be equal to 1.Take the coin and flip it twice. What is probability to get twice head?There are 4 situation, 1H and 1H, 1H and 1T, 1T and 1H, 1T and 1T.Then there are 1/4 chance to get the conin and flip it twice get both head.Every flip is an independent event.The both independent probability can * each other make what is probabilities to get both situation related.Probabilities to get the T first, H second, T third is each independent probabilities can *. So it is 1/2*1/2*1/2=1/8.Every probabilities is an INDEPENDENT event.

by 淡唁 0 0
概率相加公式的笔记

Probability of A or B=Probability of A plus Probability of B and minus Probability both A and B with overlap.Mutually Exclusive, that they both can't happen at the same t

by 淡唁 0 0
的笔记

得到一个数1的概率表示为P(1) = 1/6

by openlab 0 0
的笔记

：）

by amywoo 0 0

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独立事件的组合概率的笔记
The sum of the probabilities of all of the possible events should be equal to 1.Take the coin and flip it twice. What is probability to get twice head?There are 4 situation, 1H and 1H, 1H and 1T, 1T and 1H, 1T and 1T.Then there are 1/4 chance to get the conin and flip it twice get both head.Every flip is an independent event.The both independent probability can * each other make what is probabilities to get both situation related.Probabilities to get the T first, H second, T third is each independent probabilities can *. So it is 1/2*1/2*1/2=1/8.Every probabilities is an INDEPENDENT event.
概率相加公式的笔记
Probability of A or B=Probability of A plus Probability of B and minus Probability both A and B with overlap.Mutually Exclusive, that they both can't happen at the same t
的笔记
得到一个数1的概率表示为P(1) = 1/6
的笔记
：）